OK, here is the new puzzle…..
My friend Albert is trying to open a safe. The following numbers are on the safe door….
77 – 49 – 36 – xx
…the next number in the sequence will open the safe.
What number should Albert use to get inside the safe?
Yesterday I posted this puzzle….
Erica has two children. One of them is male. What is the probability of her other child also being male?
If you haven’t tried to solve it, have a go now. For everyone else, the answer is below….
Let’s imagine that Erica has two children. Assuming that they were not born at the exact same time, there are four possible combinations….
This will give rise to 50% males and 50% females. However, we know that one of Erica’s children is male, therefore she cannot fall into the last category, thus leaving us with…..
All of these options are equally likely, so the chances of her other child being male is one third.
Any other answers? If so, post them below.
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