On Friday I posted this puzzle…..
Imagine arranging 6 glasses in a row and filling three of them with water like this….
Every time you pick up a glass it counts as a move. What is the smallest number of moves that needs to be made in order to leave the glasses alternating full and empty?
If you have not tried to solve it, have a go now. For everyone else the answer is after the break.
One move. You pick up the glass that is third from the left, pour its contents into the glass on the far right, and put it back. Did you solve it? Any other solutions?