Erica and John are standing in the same cattle field at the same time. Erica can see the same number of bulls and cows in the field. However, John can see twice as many cows as bulls. How can this be and how many cows and bulls are there in the field?
As ever, please do NOT post your answer but feel free to say if you have solved it and how long it took. Solution on Monday!
Oh, and here is a photo of my good self helping to launch the Edinburgh International Science Festival yesterday, with Festival Director Simon Gage.
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February 25, 2011 at 5:32 am |
I quickly thought of both a straightforward solution that doesn’t put any bounds on the number of cows and bulls, and one which makes the answer very precise (and low).
February 25, 2011 at 6:31 am
I think I have the same two (types of) solution as well – one involving topography (note the photo), the other onomastics.
Took about a minute.
February 25, 2011 at 9:37 am
Yes, a number of cows often low.
February 25, 2011 at 1:52 pm
I have at least two solutions.
However, if we are looking for the minimum number of beasts that could be seen, then there is only one solution that fits…..
February 25, 2011 at 3:05 pm
Come on, this need some recognition – Richard B: “Yes, a number of cows often low.”
Hahahaha
February 25, 2011 at 3:05 pm
Come on, this need some recognition – Richard B: “Yes, a number of cows often low.”
Hahahaha
February 25, 2011 at 5:37 am |
30 seconds for two solutions.
February 25, 2011 at 5:44 am
Ditto. Moooo!
February 25, 2011 at 5:44 am |
Solved with two different solutions. The solution with a higher number of bulls and cows is the one I believe you wanted.
February 25, 2011 at 5:51 am |
I’ll add another solution to the two I already found.
February 25, 2011 at 9:49 am
I had five solutions before I even read the puzzle.
February 27, 2011 at 10:13 pm
I reply to your comment before I even read puzzle.
February 25, 2011 at 5:55 am |
I think this is too vaguely worded for a single answer.
February 25, 2011 at 6:00 pm
A little better wording could certainly make only the intended answer work, as it is there are certainly many possibilities.
February 25, 2011 at 6:06 pm
Yeah, i’m pretty sure i have richard’s intended answer, but i can think of numerous other solutions that are equally valid based on the wording… And i don’t think i’m being very tricky.
February 25, 2011 at 6:52 pm
There are three answers with one based on the solution that Richard almost certainly has in mind. The other two are slight variations and equally valid, each based on a half-way house version.
I think that any other solution would require making unwarranted assumptions – the way the land lies, odd shaped fields, visitors from Mars…
I’ll be interest to see what he comes up with. If it’s what I think it is, then I’d like to see how he could defend it as the only valid answer.
February 25, 2011 at 7:11 pm
The simplest way to cut away most of the spurious solutions would be to add “From wherever they stand in the field, looking in all directions”. Then i think the answer richard wants falls out as the most straightforward.
February 25, 2011 at 6:02 am |
1 second.
February 25, 2011 at 11:31 am
1 fs
February 25, 2011 at 6:08 am |
Zero seconds… the answer occurred to me before I finished reading the question, and was confirmed when I got to the end and there was no sudden twist.
February 26, 2011 at 12:01 pm
Minus 14 hours. The answer occurred to me the night before I read the question, I’m just that good.
February 25, 2011 at 6:20 am |
The question reminded me of the story of the father and son being involved in an accident and they are rushed to the hospital and the son is prepared for surgery however the surgeon seeing the patient says “I cannot operate as he is my son”.
This and your story depend on assumptions and there are assumptions we are being asked to make in the puzzle. You can challenge the assumption in two ways I could see straight away – but there may be more.
February 25, 2011 at 12:26 pm
I refer people to that tale all the time. The answer really makes you think about the way you assume details without even realising it.
February 25, 2011 at 6:24 am |
5 seconds for the concept.
30 seconds with a pen for the numbers
February 25, 2011 at 7:26 am
Same here. Though I got another few ideas…
February 25, 2011 at 6:27 am |
I think this is a twist on an old puzzle, and I have an answer, but I don’t think it’s the one you are after… The answer I immediately had in my head was wrong, so I had to challenge some assumptions (both the assumptions most people might make, and then the assumptions that this was the standard old puzzle). So it took a couple of minutes of scribbling and crossing out. I’ll be interested to see the “actual” answer on Monday.
February 25, 2011 at 6:44 am |
done 12 min. My 1st time. 2 answers.
February 25, 2011 at 6:47 am |
oop one more answer 3 min later
February 25, 2011 at 6:50 am |
Like the lateral thinking of number 1. My answer relies on number 3 not being true.
February 25, 2011 at 9:54 pm
Mine too. I think we’re right.
February 25, 2011 at 6:59 am |
1 answer 10 sec
February 25, 2011 at 7:05 am |
Took me 59 seconds
February 25, 2011 at 7:07 am |
1 answer, small numbers, 10 seconds, 1 altered assumption
February 25, 2011 at 7:09 am |
2 seconds
February 25, 2011 at 7:11 am |
got one more but too hammered to see if it’s a new answer. So 4 conditions total here. cya in am. fun.
February 25, 2011 at 7:20 am |
Why are there cows and bulls in the same field? Tiz not how you would normally keep them. And you certainly can’t keep bulls together.
Anyways. It didn’t take long to work out your answer.
February 25, 2011 at 7:34 am |
Three seconds for me. I hope these livestock win the Nobel Prize because they are out standing in their field.
February 25, 2011 at 12:19 pm
Haha. Made me laugh!
February 25, 2011 at 7:41 am |
my dog solved it in 4 seconds.
February 25, 2011 at 9:50 am
Mine did it in two! I don’t even have a dog!
February 25, 2011 at 8:08 am |
Solved within one minute
February 25, 2011 at 8:14 am |
I’m sure I was helped by John’s story of the doctor and his son, but whether I was or wasn’t, it took me about two minutes.
On the subject of the time taken… Just a query. Does anyone actually time how it long it takes to do these? I’m sure in some previous puzzles it has said things like ’42 seconds’ or whatever. Now, that’s pretty precise! Maybe I’m not taking it seriously enough.
February 25, 2011 at 8:14 am |
20 seconds or so for the concept. The maths after that was pretty straightforward.
February 25, 2011 at 8:15 am |
a little exhaustion & vicodin will challenge u hot shots
February 25, 2011 at 8:19 am |
No problem. Got it straight away
February 25, 2011 at 8:19 am |
I’m assuming they are both looking into the same field – John could be looking at a different field. Anyway I’ve got it, a minute or two
February 25, 2011 at 8:22 am |
I believe I have it…1 minute and 33 1/2 seconds.
February 25, 2011 at 9:04 am |
I got two solutions as I was reading it (plus a few seconds to work out the numbers), one with a small number of cattle, the other unlimited, then a couple of minutes later a third solution came to me, also with an unlimited number of cattle.
February 25, 2011 at 9:21 am |
There’s a very simple non-maths answer to this.
Moreover, standing in a field with more than one bull would a) never happen in the real world as it’s one bull per herd and b) be a very silly thing to do.
February 25, 2011 at 9:23 am |
I’ve got a question for the Friday Puzzle solving community.
Six months ago, I emailed Richard a scanned page from a puzzle book, containing what I thought would make a good future Friday Puzzle. Richard’s reply, dated 22 August 2010, said: “That’s lovely and will def use and credit!“. I replied with a scan of the solution from the same book, which I assume Richard received.
Saved in the draft folder of my blog, ready to be published at a moment’s notice, is a blog post discussing the puzzle and (in some detail) how I personally went about solving it. I planned to wait for it to show up in this series and then publish that post shortly after Richard gives us his version of the solution.
I didn’t expect to still be waiting six months later. So my question to you all is: how much longer should I wait before I reveal to the world what the puzzle was, and, after a suitable delay, publish my explanatory blog post?
The puzzle is neither particularly well-known nor particularly rare. There’s a reasonable chance puzzle connoiseurs have seen a version before, but everyone else probably hasn’t. (There is an extremely famous puzzle in the same class, but it’s different.) It’s an excellent Friday Puzzle candidate because it involves people getting killed if the puzzle is not solved.
February 25, 2011 at 9:34 am
10+5+2+1=17?
February 25, 2011 at 10:56 am
I got the answer to this in six seconds but will wait until Monday to tell you what it is
February 27, 2011 at 1:31 am
Ann … is that 17 more days? 17 more weeks? 17 more months? Or did you write that as a response to my comment by mistake?
February 27, 2011 at 9:34 pm
sooner the better to submit your link & maybe post the solution 7 days later. I have been waiting to hear what it is since you first mentioned it. I guess Richard doesn’t read these replies on a routine basis or he might reply to the many direct & indirect questions here. Shame, but business is business.
February 25, 2011 at 9:29 am |
I have several solutions. One is the answer you are probably looking for. The others have smaller numbers. (Took two minutes on these). By the time it took to write this, I had an explanation for the answer zero.
February 25, 2011 at 9:41 am |
Er…Practical restrictions would be the size of the field and how far our protagonists can see but to the problem as stated theoretically aren’t there infinitely many solutions?
In fact as for how many cows in the field I think you can make a sound case for any number from 0 up.
Either I’ve misunderstood (always possible) or this is a weak puzzle.
February 25, 2011 at 9:49 am |
I have several solutions at the moment, but the only one that fulfills all requirements of the puzzle is kind of a let down.
February 25, 2011 at 10:01 am |
It took me around 10 seconds to do the maths.
February 25, 2011 at 10:09 am |
Oh! I see. It took me until I’d read the comments, one of which sort of gave the game away.
February 25, 2011 at 11:01 am
Fortunately I solved it before reading the comments (a couple of minutes to work out the permutations), or I too would have had it spoiled by the comment you refer to. There’s always someone who has to drop unsubtle clues to demonstrate how clever they are, even after all these months of “no hints” requests.
February 25, 2011 at 10:27 am |
Came to a simple solution in 20 seconds.
February 25, 2011 at 10:30 am |
It took me all night – I had to wait until it was light enough to count them all accurately …
February 25, 2011 at 10:40 am |
I can think of two solutions – the minimum number of bovines in each is significantly under a dozen. Both solutions depend on some beasts being hidden from view of the observer, but the mechanism is different in each solution.
February 25, 2011 at 11:29 am |
This is my first time so I didnt want to be a crybaby about the hints/brags.
February 25, 2011 at 11:50 am |
Spotted mechanism within 10 seconds, worked out answer in 30.
February 25, 2011 at 11:56 am |
Very easy. Took about 30 seconds (and I didn’t even need a pencil and paper!)
February 25, 2011 at 12:07 pm |
Solved it in less that 1 minute – just a few seconds I think but wasn’t accurately timing it. I love reading all the comments – that alone is worth the puzzle. Thanks!
February 25, 2011 at 12:18 pm |
I came with several lame answers in seconds. I now have a bit better answer in 2 minutes. But I am not sure if I got the right answer.
February 25, 2011 at 12:23 pm |
Are we allowed to distract the cows by putting a dog trying to get balls out of a vase into the field?
February 25, 2011 at 1:15 pm |
I’ve got an answer and I got it quite quickly, however I’m now confused because people have written about working out the number of cows and bulls. I haven’t done any maths and have no ideas about the number of beasts in the field.
I think I will stick to my answer and see what Monday brings!!
February 25, 2011 at 1:17 pm
Just re-read question and realise I missed the bit about the number of beasts.
Oh well got other stuff to do now will have to wait until Monday now to see what the correct answer is.
February 25, 2011 at 2:49 pm |
Easy, I had it before I finished reading the question.
February 25, 2011 at 2:57 pm |
There are actually three answers to this problem. There’s the one the problem setter will almost have certainly intended, but there are two more, equally valid answers.
I think the problem setter has fallen into his/her own version of the same trap set for the rest of us…
February 25, 2011 at 3:02 pm |
I got the answer I belive is the inteded one in about 30 seconds or so.
Of course, there could be other solutions, and probably an infinite number of numbers would fit.
February 25, 2011 at 3:07 pm
Just realized my numbers were a bit out – took another 30-60 seconds fixing it.
February 25, 2011 at 3:09 pm |
Oh, wait. Got it. Obvious, once you figure it out. It was one of my solutions (mainly derived out of knowledge about cattle behaviour), I just hadn’t worked the wording of the puzzle into it, so I didn’t know how to GET to that solution.
February 25, 2011 at 8:33 pm
Or…not. Miscounted there. The proper answer would lead to fighting bulls.
February 25, 2011 at 3:55 pm |
yeah, i’m great. I solved the puzzle before i EVEN READ IT!!!.,
February 25, 2011 at 4:22 pm |
This was quickly solved. Good one though
February 25, 2011 at 4:31 pm |
I believe I have the answer. Took about 5 mins, I like that puzzle.
February 25, 2011 at 5:22 pm |
I think this is pretty easy, an old trick. Of course the real world solution makes it impossible to know the number of cattle, but easy to explain the discrepancy.
February 25, 2011 at 7:15 pm |
CAN see =/= does see. so i think it is safe to presume that both can see all the cattle, well, almost all.
February 25, 2011 at 8:07 pm |
I knew the first answer before I was done reading the question, but the second answer just occurred to me while I was writing this response.
February 25, 2011 at 8:37 pm |
There is no condition regarding fighting bulls.
February 25, 2011 at 8:38 pm |
I have answer #4 and that is all the conditions I have tested. So, done, thanks for the fun.
February 25, 2011 at 8:43 pm |
Quietly confident but I rarely suss these immediately.
February 25, 2011 at 9:13 pm |
Got it in about 6 minutes (providing that I am right)
February 25, 2011 at 9:57 pm |
If any of the conditions are dismissable as Not True then I can solve any puzzle.
February 25, 2011 at 10:09 pm |
First solution: 30 sec, second solution 2 minutes. Think i got it. Nice puzzle ! Dont watch to the photo, open your mind and think: less is more !
February 25, 2011 at 10:24 pm |
based on how this was worded, there are potentially dozens of answers. right?
February 26, 2011 at 12:13 am |
[...] It’s the Friday Puzzle! Erica and John are standing in the same cattle field at the same time. Erica can see the same number of bulls and cows [...] [...]
February 26, 2011 at 12:24 am |
Got it. 30 seconds, roughly.
February 26, 2011 at 2:25 am |
I got one solution immediately and one after reading Michael’s comment re “onomastics” to fluffy’s post. Oh, you Brits!
February 26, 2011 at 3:39 am
Oh-oh! Now I am in serious trouble!
I might need a new name so as to better blend in …
February 26, 2011 at 3:58 am |
5 seconds, I like this one, it made me feel clever.
February 26, 2011 at 4:31 am |
John realized that half the cattle are hermaphrodites!
February 26, 2011 at 6:11 am |
There are different ways the two can see different numbers of cows and bulls, but the question of the actual numbers can’t be answered unless the “how” answer proposed matches the intended. This sort of riddle annoys me.
February 26, 2011 at 7:36 am |
Under a minute.
February 26, 2011 at 10:15 am |
I figured out the twist pretty quickly, then it was just a simple simultaneous equation, leading to only one answer.
I assumed that Erica and John can see the entire field, it’s not some trick of placement or perspective.
February 26, 2011 at 10:20 am
There are two other answers besides the one you have. That’s because, without giving it away, you don’t have to make (or not make) the same assumptions about both Erica and John.
Try that, and you get two more sets of simultaneous equations to solve.
February 26, 2011 at 11:45 am |
4 conditions, 4 answers. However if some of the answers are the same number are they truly different answers (Hint: yes)
February 26, 2011 at 11:46 am |
Unless it is all done with mirrors.
February 26, 2011 at 3:59 pm |
Pretty well, honestly it is kind of confusing, but while “i” will be sleeping “i” will replace counting sheep with counting cows and bulls lol and might get to an answer lol, but regarding John, he might like to reduce drinking a bit lol so that he can be able to see better, which sometimes it isn’t recommended to see lol, the more you see the more you get confused, in religion it says that “blindness is a grace” lol, so you might like to think of those whom they do live inside churches, they chose to be kind of blinds but yet in the after life they’ll be the people’s guide lol
February 26, 2011 at 10:38 pm |
Yep, got the answer I’m sure is intended, as well as a “solution” that works without a limit on the number of cows/bulls which clearly isn’t what is intended since the question asks for a specific number.
However, I also “see” an issue with the right solution based on the physical abilities of cows/bulls and what it means to see something which I’ll save until Monday.
February 27, 2011 at 2:55 pm |
Excellent brain teaser. Took about a minute or two.
February 28, 2011 at 12:05 am |
I think I got the answer the question is looking for (echoing those above – there are others). Half a minute maybe?
February 28, 2011 at 12:35 am |
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October 17, 2011 at 8:37 am |
After reading this blog, I already fall in love with your style of writing!